Question

In the figure shown, a parallel plate capacitor has a dielectric of width d/2 and dielectric constant K = 2. The other dimensions of the dielectric are same as that of the plates. The plates $P_1$ and $P_2$ of the capacitor have area 'A' each. The energy stored in the capacitor is

• A. $\frac{{ϵ}_{0}A{V}^2}{3d}$
• B. $\frac{2{ϵ}_{0}A{V}^2}{d}$
• C. $\frac{3}{2}\frac{{ϵ}_{0}A{V}^2}{d}$
• D. $\frac{2{ϵ}_{0}A{V}^2}{3d}$

Answer 1

The correct option is D $\frac{2{ϵ}_{0}A{V}^2}{3d}$

$C$ depends upon dielectric between plates
$C=\frac{{ϵ}_{0}A}{d-t+\frac{t}{k}}=\frac{{ϵ}_{0}A}{\frac{d}{2}+\frac{d}{4}}=\frac{{ϵ}_{0}A}{3d/4}U=\frac{1}{2}C{V}^2=\frac{1}{2}\frac{4{ϵ}_{0}A}{3d}{V}^2=\frac{2{ϵ}_{0}A}{3d}{V}^2$