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Standard XII

Physics

Normal Reaction

In the figure...

Question

In the figure shown a particle is released from the position $A$ on a smooth track If $h = 3 R$ then the normal force on the particle by the track at $B$ is:

\frac{m g}{2}

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\frac{3 m g}{2}

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m g

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2 m g

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Solution

The correct option is C $m g$
$\begin{matrix} l e t t h e s p e e d a t B i s v m g h = 2 m g R + \frac{m v^{2}}{2} 3 g R = 2 g R + \frac{v^{2}}{2} L e t t h n o r m a l f o r c e a t p o i n t B i s N m g + N = \frac{m v^{2}}{R} m g + N = 2 m g N = m g H e n c e, o p t i o n C i s c o r r e c t a n s w e r \end{matrix}$

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In the figure shown a particle is released from the position A on a smooth track If h=3R then the normal force on the particle by the track at B is:

The correct option is C mgletthespeedatBisvmgh=2mgR+mv223gR=2gR+v22LetthnormalforceatpointBisNmg+N=mv2Rmg+N=2mgN=mgHence,optionCiscorrectanswer

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