wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the figure shown a ring A is rolling without sliding with a velocity v on the horizontal surface of the body B (of the same mass as A). All surfaces are smooth. B has no initial velocity. What will be the maximum height (from initial position) reached by A on B
296006_4fba611730474b24b9d19d4ba53ae7bd.png

A
3v24g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
v24g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
v22g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
v23g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3v24g
Let the ring will rise to a height h
From energy conservation we have,
K.E of linear motion+K.E of rotational motion = Potential energy of body at height h
12mv2+12Iw2=mgh
Here m=Mass of ring.
I= moment of inertia of ring=12mr2
ω= Angular velocity of ring=VR
V= Velocity of ring.
R=Radius of ring.
So we can write,
12mv2+12(12mR2)V2R2=mgh
12mv2+14mV2=mgh
3V24=gh
h=3V24g


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Work Energy and Power
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon