Question

In the figure shown, a uniform magnetic field $\left|\overrightarrow{B}\right|=0.5T$ is perpendicular to the plane of circuit. The sliding rod of length $l=0.25m$ moves uniformly with constant speed $v=4m{s}^{-1}$. If the resistance of the slides is $2\Omega$, then the current flowing through the sliding rod is :

• A. $0.1A$
• B. $0.17A$
• C. $0.08A$
• D. $0.03A$

Answer 1

The correct option is A $0.1A$

$e=Bvl$
$=0.5\times 4\times 0.25=0.5V$
$12\Omega$ and $4\Omega$ are parallel. hence their net resistance $R=3\Omega$
$i=\frac{e}{R+r}=\frac{0.5}{3+2}=0.1A$