In the figure shown, ABCD is a parallelogram. Pick the correct option

Area $(Δ A E B) = (\frac{1}{2})$ Area $(A B C D)$

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Area $(Δ A E D) = (\frac{1}{4})$ Area $(A B C D)$

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Area $(Δ A E B)$ + Area $(Δ B E C) =$ Area $(Δ A E B)$

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Area $(Δ A E D) =$ Area $(Δ B E C)$

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Solution

The correct option is A
Area $(Δ A E B) = (\frac{1}{2})$ Area $(A B C D)$

Area $(Δ A E B) = (\frac{1}{2})$ Area $(A B C D)$

Area of a triangle having the same base and height as a parallelogram is half the area of the parallelogram.

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Similar questions

A B C D

The sides BA and DC of the parallelogram ABCD are produced as shown in figure then which of the following option is correct?

Statement 1: In the figure shown, areas of both parallelogram and the triangle are equal.

Statement 2: Both the triangle and parallelogram have same base and height.

Pick the correct option

A B C D

∠ C D M

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