wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the figure shown, all surfaces are smooth. Find acceleration of all the three blocks.
251054_a4461b59af884e678c327bda12c946fe.png

A
3
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 3
Let a be the acceleration of the all three blocks.
Here all three blocks will act as a single body with mass, m=6+4+10=20kg
As force on left side is more so it will move to the right. Thus, the equation of motion of the system , ma=10040=60 N
or a=60/20=3 m/s2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motion Under Constant Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon