In the figure shown all the surface are smooth. All the blocks A, B and C are movable, positive x-axis is horizontal and positive y-axis vertical as shown. Just after the system is released from the position as shown.
In the figure shown all the surface are smooth. All the blocks A, B and C are movable, positive x-axis is horizontal and positive y-axis vertical as shown. Just after the system is released from the position as shown.
The acceleration of 'B' relative to ground directed along the inclined surface of 'C' is greater than g sin
.
The correct options are
A Acceleration of 'A' relative to ground is in negative y-direction
B Acceleration of 'A' relative to B is in positive x-direction
C The horizontal acceleration of 'B' relative to ground is in negative x-direction.
D The acceleration of 'B' relative to ground directed along the inclined surface of 'C' is greater than g sin.
(a) A will move along the (-ve) y direction as there are no horizontal forces and the net downward force will be (mg - N)
The horizontal acceleration of B with respect to ground will be in the (-ve) x direction
Due to the component of Normal force from C
(c) As A can move only in the vertical direction with respect ground its horizontal acceleration should be zero. And since B has a horizontal acceleration be the (-ve) x direction, horizontal acceleration of A with respect B will be positive.
(d) The net force along the surface of B will be greater than mB g sinθ as there will be a component from the normal force exerted by A on B. ∴ the acceleration will be greater than g sin θ.
A
Acceleration of 'A' relative to ground is in negative y-direction
B
Acceleration of 'A' relative to B is in positive x-direction
C
The horizontal acceleration of 'B' relative to ground is in negative x-direction.
D
The acceleration of 'B' relative to ground directed along the inclined surface of 'C' is greater than g sin.
(a) A will move along the (-ve) y direction as there are no horizontal forces and the net downward force will be (mg - N)
The horizontal acceleration of B with respect to ground will be in the (-ve) x direction
Due to the component of Normal force from C
(c) As A can move only in the vertical direction with respect ground its horizontal acceleration should be zero. And since B has a horizontal acceleration be the (-ve) x direction, horizontal acceleration of A with respect B will be positive.
(d) The net force along the surface of B will be greater than mB g sinθ as there will be a component from the normal force exerted by A on B. ∴ the acceleration will be greater than g sin θ.
