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Byju's Answer
Standard IX
Physics
Second Law of Motion
In the figure...
Question
In the figure shown , angle of repose is
45
0
. Find the force of friction, net force and acceleration of the block when:
1)
θ
=
30
0
2)1)
θ
=
45
0
3)1)
θ
=
60
0
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Solution
angle
g
′
repose = the angle which the incline makes with horizontal when the block placed over it just starts moving
So in that case
Refer above image
N
=
m
g
cos
θ
f
s
=
u
m
g
cos
θ
m
g
sin
θ
=
u
m
g
cos
θ
tan
θ
=
u
So
tan
54
=
u
⇒
u
=
1
Now at
θ
=
30
0
the block will not slide
at angle
θ
=
45
0
the block is just about to slide but will not move
and at angle
θ
=
60
0
m
g
sin
60
−
(
1
)
(
m
g
)
cos
60
=
m
a
g
√
3
2
−
g
2
=
a
5
(
√
3
−
1
)
=
1
⇒
a
=
3.66
m
/
s
2
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0
Similar questions
Q.
Multiple correct answers type
A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle
θ
with the horizontal. A horizontal force of 1N acts on the block through its center of mass as shown in Fig. The block remains stationary if ( take g = 10
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−
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)
a.
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b.
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and a frictional force acts on the block towards P
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Assertion :Minimum force is needed to move a block on rough surface, if
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Q.
In the given figure, two blocks of masses
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