Question

In the figure shown, area of quadrilateral ABCD is equal to the area of _______.(Given AC parallel to BE)

• A. Quadrilateral ABEC
• B. Triangle ADE
• C. Triangle ABE
• D. Triangle ACE

Answer 1

The correct option is B Triangle ADE

Triangle BAC and Triangle EAC lie on the same base AC and between the same parallels AC and BE.

Therefore, ar($△$BAC) = ar($△$EAC)

So, ar($△$BAC) + ar($△$ADC) = ar($△$EAC) + ar($△$ADC) (Adding same areas on both sides)

ar(ABCD) = ar($△$ADE).