Question

In the figure shown, assume the current in the wire to be 5 A and if B = 0.15T. The force on the section CD.

• A. Zero
• B. 0.16 N out of page
• C. 0.12 N out of page
• D. 0.12 N inside page

Answer 1

The correct option is C

0.12 N out of page

Force on section CD = BIL $sin\theta =0.15\times 5\times \frac{20}{100}sin({90}^{\circ }-\theta )=0.15\times 5\times \frac{20}{100}cos\theta )=0.15\times 5\times \frac{16}{100}N=0.12N$ Where $\theta$ is the angle between the wires.