In the figure shown, assume the current in the wire to be 5 A and flowing from A to E and if B = 0.15T. Find the force on the section CD.
BC=16cm and CD =20cm.

Zero

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0.16 N out of page

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0.12 N out of page

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0.12 N inside page

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Solution

The correct option is C 0.12 N out of page
Force on section CD

$= 0.15 \times 5 \times \frac{20}{100} c o s 37^{\circ} = 0.15 \times 5 \times \frac{16}{100} N = 0.12 N$

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