Question

In the figure shown below, find the total resistance of the circuit.

• A. $10\Omega$
• B. $18\Omega$
• C. $15\Omega$
• D. $13\Omega$

Answer 1

The correct option is A $10\Omega$


$8\Omega$ and $12\Omega$ resistors are in series, while $20\Omega$ resistor is in parallel with their equivalent resistor.

So, equivalent resistance of the circuit,

$R_{\text{eq}}=\frac{20\times (8+12)}{20+(8+12)}=10\Omega$