In the figure shown below- PS - SQ - PT - TR and - PST - P RQ - Then P QR is -triangle-

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Basic Proportionality Theorem and Its Forms

In the figure...

Question

In the figure shown below, $\frac{P S}{S Q} = \frac{P T}{T R}$ and $∠ P S T = ∠ P R Q .$ Then $△ P Q R$ is __ triangle.

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In below shown figure, $\frac{P S}{S Q} = \frac{P T}{T R}$ and $∠ P S T = ∠ P R Q$ . Then $Δ$ PQR is an __ triangle.

In the figure shown below, $\frac{P S}{S Q}$ = $\frac{P T}{T R}$ and $∠$ PST= $∠$ PRQ. Then $Δ$ PQR is an__ triangle.

In below shown figure, $\frac{P S}{S Q}$ = $\frac{P T}{T R}$ and $∠$ PST= $∠$ PRQ. Then $Δ$ PQR is __ Triangle.

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\frac{P S}{S Q}

\frac{P T}{T R}

∠

∠

Δ

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