In the figure shown below , if PSSQ= PTTR and∠PST= ∠PRQ, then ΔPQR is a/an
It is given that
PSSQ = PTTR
So, ST || QR
∴∠PST=∠PQR (corresponding Angles)
Also, it is given that
∠PST=∠PRQ
So, ∠PRQ=∠PQR
∴ PQ = PR (Sides opposite to equal angles)
i.e., ΔPQR is an isosceles triangle.