wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the figure shown below, two metallic slabs of same area of cross section and thickness having thermal conductivities 500 W/mC and 600 W/mC respectively are connected to the same temperature difference in parallel combination. Find the equivalent thermal conductivity (in W/mC)

A
600
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
500
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
550
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
450
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 550
Given,
A1=A2=A, l1=l2=l
Thermal conductivity of slab 1 (k1)=500 W/mC
Thermal conductivity of slab 2 (k2)=600 W/mC
Equivalent thermal conductivity (keq)=k1+k22=500+6002
=550 W/mC

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon