Question

In the figure shown below, $W_{AB}$ and $W_{CD}$ are workdone during process $AB$ and $CD$. Which of the following options is correct?

• A. $W_{CD}>W_{AB}$
• B. $W_{AB}>W_{CD}$
• C. $W_{AB}=W_{CD}=0$
• D. $W_{AB}=W_{CD}\ne 0$

Answer 1

The correct option is A $W_{CD}>W_{AB}$


Indicater diagram suggests,
$AB$ and $CD$ are two isobaric processes.
Work done for path $AB$, $W_{AB}=P(2V-V)=PV$
Work done for path $CD$, $W_{CD}=2P(\frac{3V}{2}-\frac{V}{2})=2PV$
$\therefore W_{CD}>W_{AB}$