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Question

In the figure shown, both the blocks are of equal mass of 10 kg and F=300 N. Find the value of tension T in the string in between the blocks.

A
100 N
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B
150 N
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C
200 N
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D
250 N
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Solution

The correct option is B 150 N
Considering the blocks to form a system, the force equation for this system can be given as
F20gsin30=20a
Here, F>20 g sin 30 so, the blocks will slide up the plane.
30020×10×12=20 a
a=10 m/s2(i)

FBD of block B

From the FBD, we can write the force equation as
FT10gsin30=10a(ii)

Using equation (i) in (ii), we get
300T50=10×10
T=150 N

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