CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the figure shown, both the blocks are of equal mass of 10 kg and F=300 N. Find the value of tension T in the string in between the blocks.

A
100 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
150 N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
200 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
250 N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 150 N
Considering the blocks to form a system, the force equation for this system can be given as
F20gsin30=20a
Here, F>20 g sin 30 so, the blocks will slide up the plane.
30020×10×12=20 a
a=10 m/s2(i)

FBD of block B

From the FBD, we can write the force equation as
FT10gsin30=10a(ii)

Using equation (i) in (ii), we get
300T50=10×10
T=150 N

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Water Slides in Amusement Parks
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon