Question

In the figure shown, coils $P$ and $Q$ are identical moving apart with same velocity $V$ . Included currents in the coils are $I_1$ and $I_2$ . Find $I_1/I_2$

Answer 1

The force acting on the loops due to magnetic field$$B$$is given as

$F=iBl$

For loop$\left(P\right)$the length is $b$

Hence the force is given as

$F=I_{1}Bb$

Similarly the force for the second coil is given as

$F=I_{2}Bl$

By equating these two equation we can find the ratio of the currents

$I_{1}Bb=I_{2}Bl$

$\frac{I_1}{I_2}=\frac{l}{b}$