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Question

# In the figure shown, find the acceleration (in m/s2) of the 2 kg body and the tension (in N) in the string. (String is massless and inextensible)

A
0,2g
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B
g,2g
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C
2g,g
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D
0,g
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Solution

## The correct option is A 0,2gFBDs of both the masses are as shown Let the direction of the acceleration a, of the systems be as shown in the figure and the tension in the string be T From the FBDs we have T−4g.sin30∘=4a⟹T−2g=4a ............(i) And, 2g−T=2a..........(ii) From eq (i) & (ii) we have a=0 Also, 2g−T=0⟹T=2g Alternate: If both the bodies are considered as a system then acceleration of the system is given by a=(Supporting Force)-(opposing Force)Total Mass=2g−4g.sin30∘6=0 Also, from the FBD of 2 Kg 2g−T=2a⟹T=2g

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