In the figure shown. Find the acceleration of the system and tension $T_{1}, T_{2}$ and $T_{3} . (Take g = 10 m / s)$

4 m / {sec}^{2}, T_{1} = 24 N, T_{2} = 42 N, T_{3} = 14 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 m / {sec}^{2}, T_{1} = 42 N, T_{2} = 24 N, T_{3} = 14 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

14 m / {sec}^{2}, T_{1} = 14 N, T_{2} = 24 N, T_{3} = 24 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 m / {sec}^{2}, T_{1} = 12 N, T_{2} = 42 N, T_{3} = 14 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $4 m / {sec}^{2}, T_{1} = 24 N, T_{2} = 42 N, T_{3} = 14 N$
$\begin{matrix} from given pictune, let net acceleration a \begin{matrix} 7 a = 7 g - T_{2} 3 a = T_{2} - 3 g 10 a = 4 g a_{2} = 30 + 12 = 42 N \end{matrix} \end{matrix}$
for, T,
$4 a = 4 g - T_{1}$
on $[T_{1} = 40 - 16 = 24 N$
- for $T_{3}$ ,
$1 \times a = T_{3} - 1 \times g$
$T_{3} = 10 + 4 = 14 N$
Ans A

Suggest Corrections

Similar questions

The plots of intensity versus wavelength of three black bodies at temperatures $T_{1}, T_{2} a n d T_{3}$ respectively are shown in figure. Their temperatures are such that

Q. The plots for intensity versus wavelength for three black bodies at temperatures

T_{1}, T_{2}, T_{3}

respectively are shown in figure. Their temperatures are such that

I, I I, I I I

are three isotherms respectively at

T_{1}, T_{2}

and

T_{3}

. The temperatures will be in the order:

Let $θ \in (0, \frac{π}{4}) a n d t_{1} = (t a n θ)^{t a n θ}, t_{2} (t a n θ)^{c o t} t_{3} = (c o t θ)^{t a n θ} a n d t_{4} (c o t θ)^{t a n θ}$ , then

Q. The plots of intensity versus wavelength for three black bodies at temperatures

T_{1}, T_{2} a n d T_{3}

respectively are as shown. Their temperature are such that

Join BYJU'S Learning Program

In the figure shown. Find the acceleration of the system and tension T1,T2 and T3.(Takeg=10m/s)

The correct option is D 4m/sec2,T1=24N,T2=42N,T3=14N from given pictune, let net acceleration a 7a=7g−T23a=T2−3g10a=4ga2=30+12=42N for, T, 4a=4g−T1 on [T1=40−16=24 N - for T3, 1×a=T3−1×g T3=10+4=14N Ans A

In the figure shown. Find the acceleration of the system and tension $T_{1}, T_{2}$ and $T_{3} . (Take g = 10 m / s)$