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Question

In the figure shown, find the tension in the string connecting the two bodies.

A
20 N
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B
30 N
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C
10 N
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D
Zero
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Solution

The correct option is D Zero
Using F=ma for both blocks without considering the tension in the spring, and thus finding a,

For block A,
2gsin302μ1gcos30=2aA
aA=g(sin300.4cos30)

For block B,
2gsin302μ1gcos30=2aB
aB=g(sin300.2cos30)
aB>aA
Hence the string will be loose T=0

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