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Question

In the figure shown find the total magnification after two successive reflections first on M1 & then on M2 is



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Solution

For M1,

u1=30 cm,f1=20 cm
1v1+1u1=1f1
1v1+130=120

1v1=130120=2360=160

v1=60 cm

For M2,

u2=+(60(10+30))=+20 cm
f2=+10 cm
1v2+120=110
v2=+20 cm

Now for M1,
m1=v1u1
For M2,
m2=v2u2

Total MT=m1×m2=v1u1×v2u2
MT = (60)(+20)(30)(+20)
=+2

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