In the figure shown, if BE∥DC and ∠EBD=∠EBA, then BD = ___.
∠ABE=∠EBD = x° (say) ...... [Given]
BE∥DC ...... [Given]
∠ABE=∠BCD = x° ....... [Corresponding angles]
∠EBD=∠BDC = x° ....... [Alternate angles]
⇒ΔBDC is an isosceles triangle.
⇒BD=BC