In the figure shown, if BE∥DCand∠EBD=∠EBA, then BD = ___.
∠ABE=∠EBD = x° (say) ...... [Given]
BE∥DC ...... [Given]
∠ABE=∠BCD = x° ....... [Corresponding angles]
∠EBD=∠BDC = x° ....... [Alternate angles]
⇒ΔBDC is an isosceles triangle.
⇒BD=DC
If a=π3e,b=3πe and c=e3π, then