Question

In the figure shown, if the diode forward voltage drops is $0.2V$, the voltage difference between $A$ and $B$ is

• A. $1.3V$
• B. $2.2V$
• C. $0.5V$
• D. $0$

Answer 1

The correct option is B $2.2V$

Current in the circuit $I=0.2mA$

Resistance of the resistor $R=5k\Omega$

Voltage drop across diode $V_d=0.2$ V

Thus potential difference between A and B $V_{AB}=IR+V_d+IR$

$\therefore$ $V_{AB}=(0.2\times {10}^{-3})(5\times {10}^3)+0.2+(0.2\times {10}^{-3})(5\times {10}^3)$

$⟹$ $V_{AB}=1+0.2+1=2.2$ volts