Question

In the figure shown, the acceleration of A is ${\overrightarrow{a}}_A=15\hat{i}+15\hat{j}.$ Then the acceleration of B is (A remains in contact with B):

• A. $5\hat{i}$
• B. $-15\hat{i}$
• C. $-10\hat{i}$
• D. $-5\hat{i}$

Answer 1

The correct option is D $-5\hat{i}$

From the figure,

$a_{A_y}cos{53}^{\circ }-a_{A_x}cos{37}^{\circ }=a_{B}cos{53}^{\circ }$

$⟹15\times \frac{3}{5}-15\times \frac{3}{5}=a_B\times \frac{3}{5}$

$⟹a_B=-5\hat{i}$