In the figure shown- the ammeter reading will be independent of R 2 whenA- R 1- R 2- rB- R 1-2 rC- r - R 1- R 2D- r -0

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Ohm's Law

In the figure...

Question

In the figure shown, the ammeter reading will be independent of $R_{2}$ when

$R_{1} + R_{2} = r$

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$R_{1} = 2 r$

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$r = R_{1} - R_{2}$

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$r = 0$

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If the sum of the areas of two circles with radii R₁ and R₂ is equal to the area of a circle of radius R, then

R_{1} + R_{2} = R

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If the sum of the areas of two circles with radii $R_{1}$ and $R_{2}$ is equal to the area of a circle of radius R then

(a) $R_{1} + R_{2} = R$

(b) $R_{1} + R_{2} > R$

(d) $R_{1}^{2} + R_{2}^{2} = R^{2}$

r_{1}

r_{2}

R

M

F_{1}

F_{2}

R_{1}

R_{2}

R_{1} + R_{2} = R

R_{1} + R_{2} > R

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R_{1}, R_{2} a n d R

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