Question

In the figure shown, the area of triangle APB is

• A. 6 $c{m}^2$
• B. 12 $c{m}^2$
• C. 24 $c{m}^2$
• D. 48 $c{m}^2$

Answer 1

The correct option is B

12 $c{m}^2$

Theorem used: If a triangle and a parallelogram are on the same base and between the same parallels, then the area of the triangle is equal to half the area of the parallelogram.

Area of ΔAPB = $\frac{1}{2}\times$Area of ABCD

Area of ABCD = $Base\times Altitude=6\times 4=24c{m}^2$

Area of ΔAPB = 12 $c{m}^2$