In the figure shown- the arms of angle AOB is-areA- The point OB- The ray OAC- The ray OBD- The rays OA and OB

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Angle

In the figure...

Question

In the figure shown, the arms of angle AOB is/are

The point O

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The ray OA

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The ray OB

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The rays OA and OB

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Solution

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Similar questions

In the figure, rays OA, OB, OC, OD and OE have the common end point O. Show that $∠ A O B + ∠ B O C + ∠ C O D + ∠ D O E + ∠ E O A = 360^{\circ}$ .

O B

{48.58}^{\circ}

O A

{157.32}^{\circ}

O A & O B

Let be two rays and let be a ray between and such that ∠AOX > ∠XOB.

Let be the bisector of ∠AOB. Prove that ∠AOX − ∠XOB = 2∠COX.

∠ A O B

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