Question

In the figure shown, the emf $2\mu F$ for which charge on $2\mu F$ capacitor is $4\mu C$ is ........

Answer 1

We know $q=CV$

$\Rightarrow V=\frac{q}{C}=2V$

$\therefore$Potential across $2\mu F$ capacitor $-2V$

From figure, potential across capacitor is $2\mu F$ capacitor is $(E-2)V$

$\therefore E-2=2$

$E=4V$