In the figure shown, the equivalent capacitance between ′A′ and ′B′ is:
A
3.75F
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B
2F
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C
21F
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D
16F
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Solution
The correct option is B2F As 3F and 6F are in series, effective capacitance between C and B is 3×63+6=2F.
Circuit can be simplified as
It is a balanced wheatstone bridge. So, 5F can be removed.
From circuit we can observe that, series setup of 1F and 2F is connected in parallel with series setup of 2F and 4F. So, effective capacitance between A and B is