In the figure shown the shaded region $A B C D A$ represents the solution set of the linear inequations $x \geq 0, y \geq 0$ and

3 x + 4 y \leq 12, x \geq 2, y \leq 1

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3 x + 4 y \leq 12, x \geq 2, y \geq 1

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3 x + 4 y \geq 12, x \leq 2, y \geq 1

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3 x + 4 y \leq 12, x \leq 2, y \geq 1

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Solution

The correct option is D $3 x + 4 y \leq 12, x \leq 2, y \geq 1$
The region $A B C D A$ (shaded represents the solution set of the inequalities.
$3 x + 4 y \leq 12, x \leq 2, y \geq 1$
$∴$ (4) is correct

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