Question

In the figure shown, the system is released from rest with both the springs in un-stretched positions. Mass of each block is $1$ kg and force constant of each spring is $10$ N/m.
Extension of vertical spring in equilibrium is?

• A. $0.33$m
• B. $0.2$m
• C. $0.6$m
• D. $0.8$m

Answer 1

The correct option is A $0.33$m

If spring $t$ is stratched be $x$, then block $2$ will move downword by $\left(x/2\right)$,

Spring $=kx$

Block $2:k\frac{x}{2}+T=Mg$

$\frac{kx}{2}+kx=Mg$

$\frac{3Kx}{2}=Mg$

$=\frac{x}{2}=\frac{Mg}{3K}=\frac{1\times 10}{3\times 10}=\frac{3.33}{10}$

$\frac{x}{2}=0.33m$