In the figure shown the velocity of lift is 2 m/s while string is winding on the motor shaft with velocity 2 m/s and block A is moving downwards with velocity of 2 m/s, the find out the velocity of block B.

2 \frac{m}{s}

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4 \frac{m}{s}

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5 \frac{m}{s}

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6 \frac{m}{s}

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Solution

The correct option is D $6 \frac{m}{s}$
${\to V}_{B, l} = 4 m / s ↑, {\to V}_{B, l} = {\to V}_{B g} - {\to V}_{l g}$

$\Rightarrow 4 m / s = {\to V}_{B g} - 2 m / s, {\to V}_{B g} = 6 m / s ↑$

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Similar questions

Q. In the figure shown the velocity of lift is

2 m / s

while string is winding on the motor shaft with velocity

2 m / s

and block

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In the figure it is shown that the velocity of lift is $2 m s^{- 1}$ while string ins winding on the motor shaft with velocity $2 m s^{- 1}$ and shaft A is moving downward with velocity $2 m s^{- 1}$ with respect lift, then find out the velocity of block B