In the figure, side AC is extended to D.
∠BCD=_______
Since, ∠BCD is an exterior angle.
Hence, it will be equal to the sum of two interior opposite angles.
So,∠BCD=∠CAB+∠CBA
In the figure, the sideCB is extended toD.
∠ABD is an_____ angle.
In the figure, the side BCof△ABC is extended to D.∠BAC=_________.