In the figure, side of square $A B C D$ is $7 c m$ . With centre $D$ and radius $D A$ . Sector $D - A X C$ is drawn. Find the area of the shaded region.

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Solution

Area of a square $= {s i d e}^{2} = 7^{2} = 49$ sq.cm

Area of sector $(D - A X C) = \frac{θ}{360} \times π r^{2} = \frac{90}{360} \times \frac{22}{7} \times 49 = 38.5$ sq,cm

Area of Shaded region $=$ area of square $A B C D -$ Area of sector $(D - A X C)$
$= 49 - 38.5 = 10.5$ sq.cm

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In the figure, side of square ABCD is 7 cm. With centre D and radius DA. Sector D−AXC is drawn. Find the area of the shaded region.

Area of a square=side2=72=49sq.cmArea of sector (D−AXC)=θ360×πr2=90360×227×49=38.5sq,cmArea of Shaded region=area of squareABCD−Area of sector (D−AXC)=49−38.5=10.5sq.cm

In the figure, side of square $A B C D$ is $7 c m$ . With centre $D$ and radius $D A$ . Sector $D - A X C$ is drawn. Find the area of the shaded region.

Area of a square $= {s i d e}^{2} = 7^{2} = 49$ sq.cm

Area of sector $(D - A X C) = \frac{θ}{360} \times π r^{2} = \frac{90}{360} \times \frac{22}{7} \times 49 = 38.5$ sq,cm

Area of Shaded region $=$ area of square $A B C D -$ Area of sector $(D - A X C)$
$= 49 - 38.5 = 10.5$ sq.cm