Question

Question 4
In the figure, the area of parallelogram ABCD is:


A) AB $\times$ BM
B) BC $\times$ BN
C) DC $\times$ DL
D) AD $\times$ DL

Answer 1

The answer is C.
We know that, the area of a parallelogram is the product of its any side and the corresponding altitude (or height).
Here, when AB is base, the height is DL.
$\therefore$ Area of parallelogram = AB $\times$ DL.
And when AD is base, the height is BM.
$\therefore$ Area of parallelogram = AD $\times$ BM
And when BC is base, the height is BM.
$\therefore$ Area of parallelogram = BC $\times$ BM
And when DC is base, the height is DL.
$\therefore$ Area of parallelogram = DC $\times$ DL

So, the area of the parallelogram is DC $\times$ DL