In the figure, the bisector of B and C meet at O. Then ∠BOC is
∠BOC=180∘ −∠2−∠4 =180∘ - ∠B2 - ∠C2 =180∘ - 90∘ + ∠A2 (Since 180∘ -∠ A = ∠ B + ∠ C) =90∘ +∠A2
In the figure, the bisector of B and C meet at O. Then ∠ BOC is
The internal bisectors of the angles B and C of a triangle ABC meet at O. Then, ∠BOC is equal to