In the figure, the distribution of energy density of the radiation emitted by a block body at a given temperature is shown. The possible temperature of the black body is
A
1500K
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B
2000K
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C
2500K
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D
3000K
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Solution
The correct option is B2000K λmT=bWhereb=2.89×10−3mK⇒T=bλm=2.89×10−31.5×10−6≈2000K