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Question

In the figure, the force with which the man should pull the rope to hold the plank in position is F. If weight of the man is 60 kg, the plank and pulleys have negligible masses, then (g=10 m/s2):
1022101_039b178979bc4e499dbf90ffaf6a6bf5.png

A
F=15 kgf
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B
F=30 kgf
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C
F=60 kgf
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D
F=120 kgf
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Solution

The correct option is A F=15 kgf
The conditions of equilibrium
Fnet=0
Man on the plank as a system
T+Nmg=0 ....(1)
For plank as a system
3TN=0 ....(2)
Substitute T from eq1 in eq2
we get 3mg3NN=0
3mg=4N
3/4mg=N
now substitute N in eq1
T=mg3/4mg
Mag of weight =60
T=6045
T=15
Thus force applied is 15kgf

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