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Question

In the figure, the length of ¯¯¯¯¯¯¯¯AC is 3 times the length of ¯¯¯¯¯¯¯¯¯CD. If B is the midpoint of ¯¯¯¯¯¯¯¯AC, and the length of ¯¯¯¯¯¯¯¯¯CD is 5, calculate the length of ¯¯¯¯¯¯¯¯¯BD.
492867_d6573eeb90be414c800dce4867af3d4a.png

A
10
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B
12.5
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C
13.5
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D
15
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Solution

The correct option is B 12.5
Given, AC=3CD and CD=5
AC=3×5=15
Also given, B is mid point of AC
BC=AC2=152=7.5
BD=BC+CD=7.5+5=12.5

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