In the figure, the velocity $V_{3}$ will be

Zero

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4 m s^{- 1}

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1 m s^{- 1}

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3 m s^{- 1}

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Solution

The correct option is C $1 m s^{- 1}$
According to equation of continuity
$A_{1} V_{1} = A_{2} V_{2} + A_{3} V_{3}$
$\Rightarrow 4 \times 0.2 = 2 \times 0.2 + 0.4 \times V_{3} \Rightarrow V_{3} = 1 m / s$

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