wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the figure, there exists a uniform magnetic field B into the plane of paper. Wire CD is in the shape of an arc and is fixed. OA and OB are the wires rotating with angular velocity ω as shown in the figure in the same plane as that of the arc about point O. If at some instant, OA=OB=1 and each wire makes angle θ=30o with y-axis, then the current through resistance R is (wire OA and OB have no resistance)
222578.PNG

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Bωl2R
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Bωl22R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Bωl24R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
answer required
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D Bωl2R
EMF induced in wire OA = 12Bl2ω with A positive wrt O
emf induced in wire OB = 12Bl2ω with O positive wrt B
Therefore total emf in the loop consisting of wire OA , OB and the arc is Bl2ω
current in loop = Bl2ωR

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motional EMF
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon