Question

In the figure, what is the potential difference between the points A and B and between B and C respectively in steady state.

• A. $V_{AB}=V_{BC}=100V$
• B. $V_{AB}=75V,V_{BC}=25V$
• C. $V_{AB}=25V,V_{BC}=75V$
• D. $V_{AB}=V_{BC}=50V$

Answer 1

The correct option is C $V_{AB}=25V,V_{BC}=75V$

Refer image (1)

capacitor x and y are in parallel .So thin capacitance will be

$C_{net}=3+3=6uF$

Capacitors m and N are in parallel

Son this net capacitance will be

$C_{net}=1+2uF$

So, the above diagram counted into

(Refer image 2)

at $t=0$ $i=0$

Now, For $V_{AB}$

(Refer image 3)

$V_A+\frac{150uc}{6uF}=V_B$

$V_A-V_b=-25v=|V_A-V_B|=25v$

$V_{AB}=25V$

For $V_{BC}$

$V_B+\frac{150uc}{2uF}=V_c$

$V_B-V_c=-75V$

$\Rightarrow |V_B-V_c|=75V\to V_{BC}=75$