Question

In the figures below, find the value of ‘x’

Answer 1

In the right angled triangle $EDF,\angle D={90}^{\circ }.$ Hence, side EF is the hypotenuse.

According to Pythagoras' theorem,

$(EF{)}^2=(ED{)}^2+(DF{)}^2$

$(17{)}^2=(x{)}^2+(8{)}^2$

$289=x^2+64$

$x^2=289-64$

$x^2=225$

$x^2=(15{)}^2$

$x=15$ units

$\therefore$ The value of x is 15 units.