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Question

Question 85

In the figures, perimeter of ΔABC = perimeter of ΔPQR. Find the area of ΔABC.

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Solution

Given, perimeterof ΔABC = perimeter of ΔPQR
Perimeter of ΔPQR=14+6+10=30 cm [ perimeter of triangle = sum of all sides]
Now, perimeter of ΔABC=AB+BC+CA
30 = AB + BC + AC
30=AB+5+1330=AB+18AB=3018=12 cm

Triangle with sides 5, 12, 13 is a right angled triangle.
Area of ΔABC=12×Base×Height
=12×5×12=5×6=30 cm2


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