Question

In the fission of ${}_{94}^{239}Pu$ by a thermal neutron, two fission fragments of equal masses and sizes are produced and four neutrons are emitted. Find the force between the two fission fragments at the moment they are produced. Given: $R_0-1.1fermi$:

Answer 1

${}_{94}^{239}Pu\to 2_Z^{A}X+4_0^{1}n2Z=94and2A=239-4Z=47andA=117So,F=G\frac{M_1{M}_2}{r^2}=\frac{6.67\times {10}^{-11}\times {(117\times {10}^{-3})}^2}{{(2.2\times {10}^{-15})}^2}F=18.864\times {10}^{16}N$