Question

In the following arrangement, an object of mass 1.2 kg is at rest at point P. If N and the F are the reaction and the force of friction, then $(g=10m{s}^{-1})$

• A. $N=6N,F=6\sqrt{3}N$
• B. $N=3N,F=3\sqrt{3}N$
• C. $N=6N,F=3N$
• D. $N=6\sqrt{3}N,F=6N$

Answer 1

The correct option is D $N=6\sqrt{3}N,F=6N$

$N=mgcos30=1.2\times 10\times \frac{\sqrt{3}}{2}=6\sqrt{3}N$

$F=mgsin30=1.2\times 10\times \frac{1}{2}=6N$