Question

In the following circuit, $18\Omega$ resistor develops 2 J/sec due to current flowing through it. The power developed across $10\Omega$ resistance is

• A. 125 W
• B. 10 W
• C. $\frac{4}{5}W$
• D. 25 W

Answer 1

The correct option is B 10 W

The given circuit can be redrawn as follows
$\frac{i_1}{i_2}=\frac{9}{18}=\frac{1}{12}$
$andi=i_1+i_2$
$\Rightarrow \frac{i}{i_1}=1+\frac{i_2}{i_1}=1+2=3$
$FromP=i^{2}R\Rightarrow \frac{P_{10\Omega }}{P_{18\Omega }}={\left(\frac{i}{i_1}\right)}^2\times \frac{10}{18}\Rightarrow P_{10\Omega }=10W$